# Example 17 - Chapter 4 Class 12 Determinants (Term 1)

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 17 Find the area of the triangle whose vertices are (3, 8), ( 4, 2) and (5, 1). The area of triangle is given by = 1 2 x1 y1 1 x2 y2 1 x3 y3 1 Here x1 = 3 , y1 = 8, x2 = 4 , y2 = 2, x3 = 5 , y3 = 1 = 1 2 3 8 1 4 2 1 5 1 1 = 1 2 3 2 1 1 1 8 4 1 5 1 +1 4 2 5 1 = 1 2 (3( 2 1) 8 ( 4 5) + 1 ( 4 10) ) = 1 2 (3 (1) 8 ( 9) + 1 ( 14)) = 1 2 (3 + 72 14) = 61 2 Thus, the required area of triangle is square units

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Chapter 4 Class 12 Determinants (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.